8y/4y=2y

Solution for 8y/4y=2y equation:

8y/4y=2y

We move all terms to the left:

8y/4y-(2y)=0


Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R


We add all the numbers together, and all the variables

-2y+8y/4y=0

We multiply all the terms by the denominator


-2y*4y+8y=0

We add all the numbers together, and all the variables

8y-2y*4y=0

Wy multiply elements

-8y^2+8y=0

a = -8; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-8)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-8}=\frac{-16}{-16}
=1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-8}=\frac{0}{-16}
=0
$