8y2+10y+3=0

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Solution for 8y2+10y+3=0 equation: 



8y^2+10y+3=0

a = 8; b = 10; c = +3;
Δ = b2-4ac
Δ = 102-4·8·3
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2}{2*8}=\frac{-12}{16}
=-3/4
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2}{2*8}=\frac{-8}{16}
=-1/2
$

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