8y2-9=23

Solution for 8y2-9=23 equation:

8y^2-9=23

We move all terms to the left:

8y^2-9-(23)=0

We add all the numbers together, and all the variables

8y^2-32=0

a = 8; b = 0; c = -32;
Δ = b2-4ac
Δ = 02-4·8·(-32)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*8}=\frac{-32}{16}
=-2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*8}=\frac{32}{16}
=2
$