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8y^2=69
We move all terms to the left:
8y^2-(69)=0
a = 8; b = 0; c = -69;
Δ = b2-4ac
Δ = 02-4·8·(-69)
Δ = 2208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2208}=\sqrt{16*138}=\sqrt{16}*\sqrt{138}=4\sqrt{138}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{138}}{2*8}=\frac{0-4\sqrt{138}}{16} =-\frac{4\sqrt{138}}{16} =-\frac{\sqrt{138}}{4} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{138}}{2*8}=\frac{0+4\sqrt{138}}{16} =\frac{4\sqrt{138}}{16} =\frac{\sqrt{138}}{4} $
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