8z+1=2(4z-1)

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Solution for 8z+1=2(4z-1) equation: 



8z+1=2(4z-1)

We move all terms to the left:

8z+1-(2(4z-1))=0



We calculate terms in parentheses: -(2(4z-1)), so:

2(4z-1)

We multiply parentheses

8z-2

Back to the equation:

-(8z-2)



We get rid of parentheses

8z-8z+2+1=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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