8z+2(2z-5)=38

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Solution for 8z+2(2z-5)=38 equation: 



8z+2(2z-5)=38

We move all terms to the left:

8z+2(2z-5)-(38)=0

We multiply parentheses

8z+4z-10-38=0

We add all the numbers together, and all the variables

12z-48=0

We move all terms containing z to the left, all other terms to the right

12z=48

z=48/12

z=4

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