8z+22=3(3z+11)-2z

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Solution for 8z+22=3(3z+11)-2z equation:



8z+22=3(3z+11)-2z
We move all terms to the left:
8z+22-(3(3z+11)-2z)=0
We calculate terms in parentheses: -(3(3z+11)-2z), so:
3(3z+11)-2z
We add all the numbers together, and all the variables
-2z+3(3z+11)
We multiply parentheses
-2z+9z+33
We add all the numbers together, and all the variables
7z+33
Back to the equation:
-(7z+33)
We get rid of parentheses
8z-7z-33+22=0
We add all the numbers together, and all the variables
z-11=0
We move all terms containing z to the left, all other terms to the right
z=11

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