8z+28=4(z+1)

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Solution for 8z+28=4(z+1) equation: 



8z+28=4(z+1)

We move all terms to the left:

8z+28-(4(z+1))=0



We calculate terms in parentheses: -(4(z+1)), so:

4(z+1)

We multiply parentheses

4z+4

Back to the equation:

-(4z+4)



We get rid of parentheses

8z-4z-4+28=0

We add all the numbers together, and all the variables

4z+24=0

We move all terms containing z to the left, all other terms to the right

4z=-24

z=-24/4

z=-6

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