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8z+4(4z-3)=4(6z+4)-4
We move all terms to the left:
8z+4(4z-3)-(4(6z+4)-4)=0
We multiply parentheses
8z+16z-(4(6z+4)-4)-12=0
We calculate terms in parentheses: -(4(6z+4)-4), so:We add all the numbers together, and all the variables
4(6z+4)-4
We multiply parentheses
24z+16-4
We add all the numbers together, and all the variables
24z+12
Back to the equation:
-(24z+12)
24z-(24z+12)-12=0
We get rid of parentheses
24z-24z-12-12=0
We add all the numbers together, and all the variables
-24!=0
There is no solution for this equation
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