8z+6=(2z-1)

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Solution for 8z+6=(2z-1) equation: 



8z+6=(2z-1)

We move all terms to the left:

8z+6-((2z-1))=0



We calculate terms in parentheses: -((2z-1)), so:

(2z-1)

We get rid of parentheses

2z-1

Back to the equation:

-(2z-1)



We get rid of parentheses

8z-2z+1+6=0

We add all the numbers together, and all the variables

6z+7=0

We move all terms containing z to the left, all other terms to the right

6z=-7

z=-7/6

z=-1+1/6

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