8z-22=3(2z-11)-z

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Solution for 8z-22=3(2z-11)-z equation:



8z-22=3(2z-11)-z
We move all terms to the left:
8z-22-(3(2z-11)-z)=0
We calculate terms in parentheses: -(3(2z-11)-z), so:
3(2z-11)-z
We add all the numbers together, and all the variables
-1z+3(2z-11)
We multiply parentheses
-1z+6z-33
We add all the numbers together, and all the variables
5z-33
Back to the equation:
-(5z-33)
We get rid of parentheses
8z-5z+33-22=0
We add all the numbers together, and all the variables
3z+11=0
We move all terms containing z to the left, all other terms to the right
3z=-11
z=-11/3
z=-3+2/3

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