8z-22=3(2z-11)-z8z-22=3(2z-11)-z

Solution for 8z-22=3(2z-11)-z8z-22=3(2z-11)-z equation:

8z-22=3(2z-11)-z8z-22=3(2z-11)-z

We move all terms to the left:

8z-22-(3(2z-11)-z8z-22)=0


We calculate terms in parentheses: -(3(2z-11)-z8z-22), so:

3(2z-11)-z8z-22

We multiply parentheses

6z-z8z-33-22

We add all the numbers together, and all the variables

6z-z8z-55

Back to the equation:

-(6z-z8z-55)


We get rid of parentheses

8z-6z+z8z+55-22=0

We add all the numbers together, and all the variables

2z+z8z+33=0

We move all terms containing z to the left, all other terms to the right

2z+z8z=-33