8z-3=4(z-3)+9+4+z

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Solution for 8z-3=4(z-3)+9+4+z equation: 



8z-3=4(z-3)+9+4+z

We move all terms to the left:

8z-3-(4(z-3)+9+4+z)=0



We calculate terms in parentheses: -(4(z-3)+9+4+z), so:

4(z-3)+9+4+z

determiningTheFunctionDomain
4(z-3)+z+9+4

We add all the numbers together, and all the variables

z+4(z-3)+13

We multiply parentheses

z+4z-12+13

We add all the numbers together, and all the variables

5z+1

Back to the equation:

-(5z+1)



We get rid of parentheses

8z-5z-1-3=0

We add all the numbers together, and all the variables

3z-4=0

We move all terms containing z to the left, all other terms to the right

3z=4

z=4/3

z=1+1/3

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