8z=6(2z+1)

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Solution for 8z=6(2z+1) equation: 



8z=6(2z+1)

We move all terms to the left:

8z-(6(2z+1))=0



We calculate terms in parentheses: -(6(2z+1)), so:

6(2z+1)

We multiply parentheses

12z+6

Back to the equation:

-(12z+6)



We get rid of parentheses

8z-12z-6=0

We add all the numbers together, and all the variables

-4z-6=0

We move all terms containing z to the left, all other terms to the right

-4z=6

z=6/-4

z=-1+1/2

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