9((135-3x)/5)+7x=279

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Solution for 9((135-3x)/5)+7x=279 equation: 



9((135-3x)/5)+7x=279

We move all terms to the left:

9((135-3x)/5)+7x-(279)=0

We add all the numbers together, and all the variables

9((-3x+135)/5)+7x-279=0

We add all the numbers together, and all the variables

7x+9((-3x+135)/5)-279=0

We multiply all the terms by the denominator


7x*5)+9((-3x+135)-279*5)=0

We add all the numbers together, and all the variables

7x*5)+9((-3x+135)=0

Wy multiply elements

35x^2=0

a = 35; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·35·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{70}=0$

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