9(-1-2x)+12(x-3)=7-2(9-5x)

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Solution for 9(-1-2x)+12(x-3)=7-2(9-5x) equation: 



9(-1-2x)+12(x-3)=7-2(9-5x)

We move all terms to the left:

9(-1-2x)+12(x-3)-(7-2(9-5x))=0

We add all the numbers together, and all the variables

9(-2x-1)+12(x-3)-(7-2(-5x+9))=0

We multiply parentheses

-18x+12x-(7-2(-5x+9))-9-36=0



We calculate terms in parentheses: -(7-2(-5x+9)), so:

7-2(-5x+9)

determiningTheFunctionDomain
-2(-5x+9)+7

We multiply parentheses

10x-18+7

We add all the numbers together, and all the variables

10x-11

Back to the equation:

-(10x-11)



We add all the numbers together, and all the variables

-6x-(10x-11)-45=0

We get rid of parentheses

-6x-10x+11-45=0

We add all the numbers together, and all the variables

-16x-34=0

We move all terms containing x to the left, all other terms to the right

-16x=34

x=34/-16

x=-2+1/8

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