9(-3r+-11)*r=10

Solution for 9(-3r+-11)*r=10 equation:

9(-3r+-11)*r=10

We move all terms to the left:

9(-3r+-11)*r-(10)=0

We add all the numbers together, and all the variables

9(-3r-11)*r-10=0

We multiply parentheses

-27r^2-99r-10=0

a = -27; b = -99; c = -10;
Δ = b2-4ac
Δ = -992-4·(-27)·(-10)
Δ = 8721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8721}=\sqrt{9*969}=\sqrt{9}*\sqrt{969}=3\sqrt{969}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-99)-3\sqrt{969}}{2*-27}=\frac{99-3\sqrt{969}}{-54}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-99)+3\sqrt{969}}{2*-27}=\frac{99+3\sqrt{969}}{-54}
$