9(1+c)=8(c-1)

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Solution for 9(1+c)=8(c-1) equation:


Simplifying
9(1 + c) = 8(c + -1)
(1 * 9 + c * 9) = 8(c + -1)
(9 + 9c) = 8(c + -1)

Reorder the terms:
9 + 9c = 8(-1 + c)
9 + 9c = (-1 * 8 + c * 8)
9 + 9c = (-8 + 8c)

Solving
9 + 9c = -8 + 8c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8c' to each side of the equation.
9 + 9c + -8c = -8 + 8c + -8c

Combine like terms: 9c + -8c = 1c
9 + 1c = -8 + 8c + -8c

Combine like terms: 8c + -8c = 0
9 + 1c = -8 + 0
9 + 1c = -8

Add '-9' to each side of the equation.
9 + -9 + 1c = -8 + -9

Combine like terms: 9 + -9 = 0
0 + 1c = -8 + -9
1c = -8 + -9

Combine like terms: -8 + -9 = -17
1c = -17

Divide each side by '1'.
c = -17

Simplifying
c = -17

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