9(1/3x+1)=(x+23/9)9

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Solution for 9(1/3x+1)=(x+23/9)9 equation: 



9(1/3x+1)=(x+23/9)9

We move all terms to the left:

9(1/3x+1)-((x+23/9)9)=0



Domain of the equation: 3x+1)!=0

x∈R



We add all the numbers together, and all the variables

9(1/3x+1)-((+x+23/9)9)=0

We multiply parentheses

9x-((+x+23/9)9)+9=0

We multiply all the terms by the denominator


9x*9)9)-((+x+23+9*9)9)=0

We add all the numbers together, and all the variables

9x*9)9)-((x+104)9)=0

We add all the numbers together, and all the variables

9x*9)9)-((x=0

Wy multiply elements

81x^2=0

a = 81; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·81·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{162}=0$

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