9(1/9)c=9(18)

Solution for 9(1/9)c=9(18) equation:

9(1/9)c=9(18)

We move all terms to the left:

9(1/9)c-(9(18))=0


Domain of the equation: 9)c!=0

c!=0/1

c!=0

c∈R


determiningTheFunctionDomain
9(1/9)c-918=0

We add all the numbers together, and all the variables

9(+1/9)c-918=0

We multiply parentheses

9c^2-918=0

a = 9; b = 0; c = -918;
Δ = b2-4ac
Δ = 02-4·9·(-918)
Δ = 33048
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{33048}=\sqrt{324*102}=\sqrt{324}*\sqrt{102}=18\sqrt{102}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{102}}{2*9}=\frac{0-18\sqrt{102}}{18}
=-\frac{18\sqrt{102}}{18}
=-\sqrt{102}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{102}}{2*9}=\frac{0+18\sqrt{102}}{18}
=\frac{18\sqrt{102}}{18}
=\sqrt{102}
$