9(10+q)+12=48

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Solution for 9(10+q)+12=48 equation: 



9(10+q)+12=48

We move all terms to the left:

9(10+q)+12-(48)=0

We add all the numbers together, and all the variables

9(q+10)+12-48=0

We add all the numbers together, and all the variables

9(q+10)-36=0

We multiply parentheses

9q+90-36=0

We add all the numbers together, and all the variables

9q+54=0

We move all terms containing q to the left, all other terms to the right

9q=-54

q=-54/9

q=-6

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