9(11+6v)+10v=2(1+5v)-11

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Solution for 9(11+6v)+10v=2(1+5v)-11 equation: 



9(11+6v)+10v=2(1+5v)-11

We move all terms to the left:

9(11+6v)+10v-(2(1+5v)-11)=0

We add all the numbers together, and all the variables

9(6v+11)+10v-(2(5v+1)-11)=0

We add all the numbers together, and all the variables

10v+9(6v+11)-(2(5v+1)-11)=0

We multiply parentheses

10v+54v-(2(5v+1)-11)+99=0



We calculate terms in parentheses: -(2(5v+1)-11), so:

2(5v+1)-11

We multiply parentheses

10v+2-11

We add all the numbers together, and all the variables

10v-9

Back to the equation:

-(10v-9)



We add all the numbers together, and all the variables

64v-(10v-9)+99=0

We get rid of parentheses

64v-10v+9+99=0

We add all the numbers together, and all the variables

54v+108=0

We move all terms containing v to the left, all other terms to the right

54v=-108

v=-108/54

v=-2

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