9(11-5)=3(3k-9)

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Solution for 9(11-5)=3(3k-9) equation: 



9(11-5)=3(3k-9)

We move all terms to the left:

9(11-5)-(3(3k-9))=0

We add all the numbers together, and all the variables

-(3(3k-9))+96=0



We calculate terms in parentheses: -(3(3k-9)), so:

3(3k-9)

We multiply parentheses

9k-27

Back to the equation:

-(9k-27)



We get rid of parentheses

-9k+27+96=0

We add all the numbers together, and all the variables

-9k+123=0

We move all terms containing k to the left, all other terms to the right

-9k=-123

k=-123/-9

k=13+2/3

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