9(11-k)=3(3k-7)

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Solution for 9(11-k)=3(3k-7) equation: 



9(11-k)=3(3k-7)

We move all terms to the left:

9(11-k)-(3(3k-7))=0

We add all the numbers together, and all the variables

9(-1k+11)-(3(3k-7))=0

We multiply parentheses

-9k-(3(3k-7))+99=0



We calculate terms in parentheses: -(3(3k-7)), so:

3(3k-7)

We multiply parentheses

9k-21

Back to the equation:

-(9k-21)



We get rid of parentheses

-9k-9k+21+99=0

We add all the numbers together, and all the variables

-18k+120=0

We move all terms containing k to the left, all other terms to the right

-18k=-120

k=-120/-18

k=6+2/3

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