9(1k-2)=3(k+4)

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Solution for 9(1k-2)=3(k+4) equation: 



9(1k-2)=3(k+4)

We move all terms to the left:

9(1k-2)-(3(k+4))=0

We add all the numbers together, and all the variables

9(k-2)-(3(k+4))=0

We multiply parentheses

9k-(3(k+4))-18=0



We calculate terms in parentheses: -(3(k+4)), so:

3(k+4)

We multiply parentheses

3k+12

Back to the equation:

-(3k+12)



We get rid of parentheses

9k-3k-12-18=0

We add all the numbers together, and all the variables

6k-30=0

We move all terms containing k to the left, all other terms to the right

6k=30

k=30/6

k=5

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