9(1x-3)+8=7x+11

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Solution for 9(1x-3)+8=7x+11 equation: 



9(1x-3)+8=7x+11

We move all terms to the left:

9(1x-3)+8-(7x+11)=0

We add all the numbers together, and all the variables

9(x-3)-(7x+11)+8=0

We multiply parentheses

9x-(7x+11)-27+8=0

We get rid of parentheses

9x-7x-11-27+8=0

We add all the numbers together, and all the variables

2x-30=0

We move all terms containing x to the left, all other terms to the right

2x=30

x=30/2

x=15

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