9(2+c)=8(c-5)

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Solution for 9(2+c)=8(c-5) equation: 



9(2+c)=8(c-5)

We move all terms to the left:

9(2+c)-(8(c-5))=0

We add all the numbers together, and all the variables

9(c+2)-(8(c-5))=0

We multiply parentheses

9c-(8(c-5))+18=0



We calculate terms in parentheses: -(8(c-5)), so:

8(c-5)

We multiply parentheses

8c-40

Back to the equation:

-(8c-40)



We get rid of parentheses

9c-8c+40+18=0

We add all the numbers together, and all the variables

c+58=0

We move all terms containing c to the left, all other terms to the right

c=-58

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