9(2-1)+3(5+2j)=2(7-2j)-4(j-1)

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Solution for 9(2-1)+3(5+2j)=2(7-2j)-4(j-1) equation: 



9(2-1)+3(5+2j)=2(7-2j)-4(j-1)

We move all terms to the left:

9(2-1)+3(5+2j)-(2(7-2j)-4(j-1))=0

We add all the numbers together, and all the variables

3(2j+5)-(2(-2j+7)-4(j-1))+91=0

We multiply parentheses

6j-(2(-2j+7)-4(j-1))+15+91=0



We calculate terms in parentheses: -(2(-2j+7)-4(j-1)), so:

2(-2j+7)-4(j-1)

We multiply parentheses

-4j-4j+14+4

We add all the numbers together, and all the variables

-8j+18

Back to the equation:

-(-8j+18)



We add all the numbers together, and all the variables

6j-(-8j+18)+106=0

We get rid of parentheses

6j+8j-18+106=0

We add all the numbers together, and all the variables

14j+88=0

We move all terms containing j to the left, all other terms to the right

14j=-88

j=-88/14

j=-6+2/7

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