9(2-3r)-29=8r-(r-23)

Solution for 9(2-3r)-29=8r-(r-23) equation:

9(2-3r)-29=8r-(r-23)

We move all terms to the left:

9(2-3r)-29-(8r-(r-23))=0

We add all the numbers together, and all the variables

9(-3r+2)-(8r-(r-23))-29=0

We multiply parentheses

-27r-(8r-(r-23))+18-29=0


We calculate terms in parentheses: -(8r-(r-23)), so:

8r-(r-23)

We get rid of parentheses

8r-r+23

We add all the numbers together, and all the variables

7r+23

Back to the equation:

-(7r+23)


We add all the numbers together, and all the variables

-27r-(7r+23)-11=0

We get rid of parentheses

-27r-7r-23-11=0

We add all the numbers together, and all the variables

-34r-34=0

We move all terms containing r to the left, all other terms to the right

-34r=34

r=34/-34

r=-1