9(2-3x)-29=8x-(x-2)

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Solution for 9(2-3x)-29=8x-(x-2) equation: 



9(2-3x)-29=8x-(x-2)

We move all terms to the left:

9(2-3x)-29-(8x-(x-2))=0

We add all the numbers together, and all the variables

9(-3x+2)-(8x-(x-2))-29=0

We multiply parentheses

-27x-(8x-(x-2))+18-29=0



We calculate terms in parentheses: -(8x-(x-2)), so:

8x-(x-2)

We get rid of parentheses

8x-x+2

We add all the numbers together, and all the variables

7x+2

Back to the equation:

-(7x+2)



We add all the numbers together, and all the variables

-27x-(7x+2)-11=0

We get rid of parentheses

-27x-7x-2-11=0

We add all the numbers together, and all the variables

-34x-13=0

We move all terms containing x to the left, all other terms to the right

-34x=13

x=13/-34

x=-13/34

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