9(2-3x)-29=8x-4(x-23)

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Solution for 9(2-3x)-29=8x-4(x-23) equation: 



9(2-3x)-29=8x-4(x-23)

We move all terms to the left:

9(2-3x)-29-(8x-4(x-23))=0

We add all the numbers together, and all the variables

9(-3x+2)-(8x-4(x-23))-29=0

We multiply parentheses

-27x-(8x-4(x-23))+18-29=0



We calculate terms in parentheses: -(8x-4(x-23)), so:

8x-4(x-23)

We multiply parentheses

8x-4x+92

We add all the numbers together, and all the variables

4x+92

Back to the equation:

-(4x+92)



We add all the numbers together, and all the variables

-27x-(4x+92)-11=0

We get rid of parentheses

-27x-4x-92-11=0

We add all the numbers together, and all the variables

-31x-103=0

We move all terms containing x to the left, all other terms to the right

-31x=103

x=103/-31

x=-3+10/31

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