9(2-3x)-29=8x-x-(x-23)

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Solution for 9(2-3x)-29=8x-x-(x-23) equation: 



9(2-3x)-29=8x-x-(x-23)

We move all terms to the left:

9(2-3x)-29-(8x-x-(x-23))=0

We add all the numbers together, and all the variables

9(-3x+2)-(8x-x-(x-23))-29=0

We multiply parentheses

-27x-(8x-x-(x-23))+18-29=0



We calculate terms in parentheses: -(8x-x-(x-23)), so:

8x-x-(x-23)

We add all the numbers together, and all the variables

7x-(x-23)

We get rid of parentheses

7x-x+23

We add all the numbers together, and all the variables

6x+23

Back to the equation:

-(6x+23)



We add all the numbers together, and all the variables

-27x-(6x+23)-11=0

We get rid of parentheses

-27x-6x-23-11=0

We add all the numbers together, and all the variables

-33x-34=0

We move all terms containing x to the left, all other terms to the right

-33x=34

x=34/-33

x=-1+1/33

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