9(2-3y)=-10(5+y)

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Solution for 9(2-3y)=-10(5+y) equation:



9(2-3y)=-10(5+y)
We move all terms to the left:
9(2-3y)-(-10(5+y))=0
We add all the numbers together, and all the variables
9(-3y+2)-(-10(y+5))=0
We multiply parentheses
-27y-(-10(y+5))+18=0
We calculate terms in parentheses: -(-10(y+5)), so:
-10(y+5)
We multiply parentheses
-10y-50
Back to the equation:
-(-10y-50)
We get rid of parentheses
-27y+10y+50+18=0
We add all the numbers together, and all the variables
-17y+68=0
We move all terms containing y to the left, all other terms to the right
-17y=-68
y=-68/-17
y=+4

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