9(2-j)+3(5+2)=2(7-2j)-4(j-1)

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Solution for 9(2-j)+3(5+2)=2(7-2j)-4(j-1) equation:


9(2-j)+3(5+2)=2(7-2j)-4(j-1)

We simplify the equation to the form, which is simple to understand
9(2-j)+3(5+2)=2(7-2j)-4(j-1)

Simplifying terms in parentheses
9*(2-j)+3*(+7)=2*(7-2j)-4*(j-1)

Reorder the terms in parentheses
+(+18-9j)+3*(+7)=2*(7-2j)-4*(j-1)

Remove unnecessary parentheses
+18-9j+3+*(+7+)=+2+*(+7-2j+)-4+*(+j-1+)

Reorder the terms in parentheses
+18-9j+(+21)=2*(7-2j)-4*(j-1)

Remove unnecessary parentheses
+18-9j+21=+2+*(+7-2j+)-4+*(+j-1+)

Reorder the terms in parentheses
+18-9j+21=+(+14-4j)-4*(j-1)

Remove unnecessary parentheses
+18-9j+21=+14-4j-4+*(+j-1+)

Reorder the terms in parentheses
+18-9j+21=+14-4j+(-4j+4)

Remove unnecessary parentheses
+18-9j+21=+14-4j-4j+4

We move all terms containing j to the left and all other terms to the right.
-9j+4j+4j=+14+4-18-21

We simplify left and right side of the equation.
-1j=-21

We divide both sides of the equation by -1 to get j.
j=21

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