9(2-j)+3(5-2j)=2(7-2j)-4(j-1)

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Solution for 9(2-j)+3(5-2j)=2(7-2j)-4(j-1) equation: 



9(2-j)+3(5-2j)=2(7-2j)-4(j-1)

We move all terms to the left:

9(2-j)+3(5-2j)-(2(7-2j)-4(j-1))=0

We add all the numbers together, and all the variables

9(-1j+2)+3(-2j+5)-(2(-2j+7)-4(j-1))=0

We multiply parentheses

-9j-6j-(2(-2j+7)-4(j-1))+18+15=0



We calculate terms in parentheses: -(2(-2j+7)-4(j-1)), so:

2(-2j+7)-4(j-1)

We multiply parentheses

-4j-4j+14+4

We add all the numbers together, and all the variables

-8j+18

Back to the equation:

-(-8j+18)



We add all the numbers together, and all the variables

-15j-(-8j+18)+33=0

We get rid of parentheses

-15j+8j-18+33=0

We add all the numbers together, and all the variables

-7j+15=0

We move all terms containing j to the left, all other terms to the right

-7j=-15

j=-15/-7

j=2+1/7

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