9(2-q)=3(q-12)

Solution for 9(2-q)=3(q-12) equation:

9(2-q)=3(q-12)

We move all terms to the left:

9(2-q)-(3(q-12))=0

We add all the numbers together, and all the variables

9(-1q+2)-(3(q-12))=0

We multiply parentheses

-9q-(3(q-12))+18=0


We calculate terms in parentheses: -(3(q-12)), so:

3(q-12)

We multiply parentheses

3q-36

Back to the equation:

-(3q-36)


We get rid of parentheses

-9q-3q+36+18=0

We add all the numbers together, and all the variables

-12q+54=0

We move all terms containing q to the left, all other terms to the right

-12q=-54

q=-54/-12

q=4+1/2