9(2-s)-(5s+1)=5(3-s)-10s

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Solution for 9(2-s)-(5s+1)=5(3-s)-10s equation: 



9(2-s)-(5s+1)=5(3-s)-10s

We move all terms to the left:

9(2-s)-(5s+1)-(5(3-s)-10s)=0

We add all the numbers together, and all the variables

9(-1s+2)-(5s+1)-(5(-1s+3)-10s)=0

We multiply parentheses

-9s-(5s+1)-(5(-1s+3)-10s)+18=0

We get rid of parentheses

-9s-5s-(5(-1s+3)-10s)-1+18=0



We calculate terms in parentheses: -(5(-1s+3)-10s), so:

5(-1s+3)-10s

We add all the numbers together, and all the variables

-10s+5(-1s+3)

We multiply parentheses

-10s-5s+15

We add all the numbers together, and all the variables

-15s+15

Back to the equation:

-(-15s+15)



We add all the numbers together, and all the variables

-14s-(-15s+15)+17=0

We get rid of parentheses

-14s+15s-15+17=0

We add all the numbers together, and all the variables

s+2=0

We move all terms containing s to the left, all other terms to the right

s=-2

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