9(2c+1)=6-(13-2c)

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Solution for 9(2c+1)=6-(13-2c) equation: 



9(2c+1)=6-(13-2c)

We move all terms to the left:

9(2c+1)-(6-(13-2c))=0

We add all the numbers together, and all the variables

9(2c+1)-(6-(-2c+13))=0

We multiply parentheses

18c-(6-(-2c+13))+9=0



We calculate terms in parentheses: -(6-(-2c+13)), so:

6-(-2c+13)

determiningTheFunctionDomain
-(-2c+13)+6

We get rid of parentheses

2c-13+6

We add all the numbers together, and all the variables

2c-7

Back to the equation:

-(2c-7)



We get rid of parentheses

18c-2c+7+9=0

We add all the numbers together, and all the variables

16c+16=0

We move all terms containing c to the left, all other terms to the right

16c=-16

c=-16/16

c=-1

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