9(2d-10)-7=7(4d-1)

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Solution for 9(2d-10)-7=7(4d-1) equation: 



9(2d-10)-7=7(4d-1)

We move all terms to the left:

9(2d-10)-7-(7(4d-1))=0

We multiply parentheses

18d-(7(4d-1))-90-7=0



We calculate terms in parentheses: -(7(4d-1)), so:

7(4d-1)

We multiply parentheses

28d-7

Back to the equation:

-(28d-7)



We add all the numbers together, and all the variables

18d-(28d-7)-97=0

We get rid of parentheses

18d-28d+7-97=0

We add all the numbers together, and all the variables

-10d-90=0

We move all terms containing d to the left, all other terms to the right

-10d=90

d=90/-10

d=-9

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