9(2k+3)+2=11(k+-4)

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Solution for 9(2k+3)+2=11(k+-4) equation: 



9(2k+3)+2=11(k+-4)

We move all terms to the left:

9(2k+3)+2-(11(k+-4))=0

We add all the numbers together, and all the variables

9(2k+3)-(11(k-4))+2=0

We multiply parentheses

18k-(11(k-4))+27+2=0



We calculate terms in parentheses: -(11(k-4)), so:

11(k-4)

We multiply parentheses

11k-44

Back to the equation:

-(11k-44)



We add all the numbers together, and all the variables

18k-(11k-44)+29=0

We get rid of parentheses

18k-11k+44+29=0

We add all the numbers together, and all the variables

7k+73=0

We move all terms containing k to the left, all other terms to the right

7k=-73

k=-73/7

k=-10+3/7

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