9(2k+3)+2=11(k+1)

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Solution for 9(2k+3)+2=11(k+1) equation:



9(2k+3)+2=11(k+1)
We move all terms to the left:
9(2k+3)+2-(11(k+1))=0
We multiply parentheses
18k-(11(k+1))+27+2=0
We calculate terms in parentheses: -(11(k+1)), so:
11(k+1)
We multiply parentheses
11k+11
Back to the equation:
-(11k+11)
We add all the numbers together, and all the variables
18k-(11k+11)+29=0
We get rid of parentheses
18k-11k-11+29=0
We add all the numbers together, and all the variables
7k+18=0
We move all terms containing k to the left, all other terms to the right
7k=-18
k=-18/7
k=-2+4/7

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