9(2k+3)+2=11k-+5

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Solution for 9(2k+3)+2=11k-+5 equation: 



9(2k+3)+2=11k-+5

We move all terms to the left:

9(2k+3)+2-(11k-+5)=0

We add all the numbers together, and all the variables

9(2k+3)-(+11k)+2=0

We multiply parentheses

18k-(+11k)+27+2=0

We get rid of parentheses

18k-11k+27+2=0

We add all the numbers together, and all the variables

7k+29=0

We move all terms containing k to the left, all other terms to the right

7k=-29

k=-29/7

k=-4+1/7

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