9(2k+3)+2=k-5

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Solution for 9(2k+3)+2=k-5 equation: 



9(2k+3)+2=k-5

We move all terms to the left:

9(2k+3)+2-(k-5)=0

We multiply parentheses

18k-(k-5)+27+2=0

We get rid of parentheses

18k-k+5+27+2=0

We add all the numbers together, and all the variables

17k+34=0

We move all terms containing k to the left, all other terms to the right

17k=-34

k=-34/17

k=-2

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