9(2k+3)+3=11(k-5)

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Solution for 9(2k+3)+3=11(k-5) equation: 



9(2k+3)+3=11(k-5)

We move all terms to the left:

9(2k+3)+3-(11(k-5))=0

We multiply parentheses

18k-(11(k-5))+27+3=0



We calculate terms in parentheses: -(11(k-5)), so:

11(k-5)

We multiply parentheses

11k-55

Back to the equation:

-(11k-55)



We add all the numbers together, and all the variables

18k-(11k-55)+30=0

We get rid of parentheses

18k-11k+55+30=0

We add all the numbers together, and all the variables

7k+85=0

We move all terms containing k to the left, all other terms to the right

7k=-85

k=-85/7

k=-12+1/7

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