9(2k-3)-28=11(k-5)+7k

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Solution for 9(2k-3)-28=11(k-5)+7k equation: 


Simplifying
9(2k + -3) + -28 = 11(k + -5) + 7k

Reorder the terms:
9(-3 + 2k) + -28 = 11(k + -5) + 7k
(-3 * 9 + 2k * 9) + -28 = 11(k + -5) + 7k
(-27 + 18k) + -28 = 11(k + -5) + 7k

Reorder the terms:
-27 + -28 + 18k = 11(k + -5) + 7k

Combine like terms: -27 + -28 = -55
-55 + 18k = 11(k + -5) + 7k

Reorder the terms:
-55 + 18k = 11(-5 + k) + 7k
-55 + 18k = (-5 * 11 + k * 11) + 7k
-55 + 18k = (-55 + 11k) + 7k

Combine like terms: 11k + 7k = 18k
-55 + 18k = -55 + 18k

Add '55' to each side of the equation.
-55 + 55 + 18k = -55 + 55 + 18k

Combine like terms: -55 + 55 = 0
0 + 18k = -55 + 55 + 18k
18k = -55 + 55 + 18k

Combine like terms: -55 + 55 = 0
18k = 0 + 18k
18k = 18k

Add '-18k' to each side of the equation.
18k + -18k = 18k + -18k

Combine like terms: 18k + -18k = 0
0 = 18k + -18k

Combine like terms: 18k + -18k = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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