9(2n+3)=6(9n+3)+6

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Solution for 9(2n+3)=6(9n+3)+6 equation:



9(2n+3)=6(9n+3)+6
We move all terms to the left:
9(2n+3)-(6(9n+3)+6)=0
We multiply parentheses
18n-(6(9n+3)+6)+27=0
We calculate terms in parentheses: -(6(9n+3)+6), so:
6(9n+3)+6
We multiply parentheses
54n+18+6
We add all the numbers together, and all the variables
54n+24
Back to the equation:
-(54n+24)
We get rid of parentheses
18n-54n-24+27=0
We add all the numbers together, and all the variables
-36n+3=0
We move all terms containing n to the left, all other terms to the right
-36n=-3
n=-3/-36
n=1/12

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