9(2n+3)=7(8n+5)+6

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Solution for 9(2n+3)=7(8n+5)+6 equation: 



9(2n+3)=7(8n+5)+6

We move all terms to the left:

9(2n+3)-(7(8n+5)+6)=0

We multiply parentheses

18n-(7(8n+5)+6)+27=0



We calculate terms in parentheses: -(7(8n+5)+6), so:

7(8n+5)+6

We multiply parentheses

56n+35+6

We add all the numbers together, and all the variables

56n+41

Back to the equation:

-(56n+41)



We get rid of parentheses

18n-56n-41+27=0

We add all the numbers together, and all the variables

-38n-14=0

We move all terms containing n to the left, all other terms to the right

-38n=14

n=14/-38

n=-7/19

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