9(2q+3)+2=11(q-5)

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Solution for 9(2q+3)+2=11(q-5) equation: 



9(2q+3)+2=11(q-5)

We move all terms to the left:

9(2q+3)+2-(11(q-5))=0

We multiply parentheses

18q-(11(q-5))+27+2=0



We calculate terms in parentheses: -(11(q-5)), so:

11(q-5)

We multiply parentheses

11q-55

Back to the equation:

-(11q-55)



We add all the numbers together, and all the variables

18q-(11q-55)+29=0

We get rid of parentheses

18q-11q+55+29=0

We add all the numbers together, and all the variables

7q+84=0

We move all terms containing q to the left, all other terms to the right

7q=-84

q=-84/7

q=-12

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