9(2r-1)/7=(9r-3)/5

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Solution for 9(2r-1)/7=(9r-3)/5 equation: 



9(2r-1)/7=(9r-3)/5

We move all terms to the left:

9(2r-1)/7-((9r-3)/5)=0

We calculate fractions


18r/()+(-((9r-3)*7)/()=0



We calculate terms in parentheses: +(-((9r-3)*7)/(), so:

-((9r-3)*7)/(

We multiply all the terms by the denominator


-((9r-3)*7)



We calculate terms in parentheses: -((9r-3)*7), so:

(9r-3)*7

We multiply parentheses

63r-21

Back to the equation:

-(63r-21)



We get rid of parentheses

-63r+21

Back to the equation:

+(-63r+21)



We get rid of parentheses

18r/()-63r+21=0

We multiply all the terms by the denominator


18r-63r*()+21*()=0

We add all the numbers together, and all the variables

18r-63r*()=0

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