9(2r-3)-r=3(3r+2)

Solution for 9(2r-3)-r=3(3r+2) equation:

9(2r-3)-r=3(3r+2)

We move all terms to the left:

9(2r-3)-r-(3(3r+2))=0

We add all the numbers together, and all the variables

-1r+9(2r-3)-(3(3r+2))=0

We multiply parentheses

-1r+18r-(3(3r+2))-27=0


We calculate terms in parentheses: -(3(3r+2)), so:

3(3r+2)

We multiply parentheses

9r+6

Back to the equation:

-(9r+6)


We add all the numbers together, and all the variables

17r-(9r+6)-27=0

We get rid of parentheses

17r-9r-6-27=0

We add all the numbers together, and all the variables

8r-33=0

We move all terms containing r to the left, all other terms to the right

8r=33

r=33/8

r=4+1/8